Counting states in heterotic SO(32) string theory | A First Course in String Theory

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At any mass level of the heterotic string, the spacetime bosons are obtained by “tensoring” *all* the left states (NS’+ and R’+) with with the right-moving NS+ states with .

Similarly, the spacetime fermions are obtained by tensoring all the left states (NS’+ and R’+) with with the right-moving R- states with .

c) Are there tachyonic states in heterotic string theory?

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— This answer is my guess. —

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The left NS’+ sector:

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The left R’+ sector:

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The right-moving NS+ states:

NS+ equations of (14.38):

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The R- states (that used as right-moving states):

Mass levels of R- and R+ (Equations 14.54):

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There are no tachyonic states in heterotic string theory, since neither of the right-moving parts (NS+ and R-) has states with .

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— This answer is my guess. —

— Me@2018-11-22 12:00:30 PM

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2018.11.22 Thursday (c) All rights reserved by ACHK