Consistent histories, 7

In quantum mechanics, the consistent histories (also referred to as decoherent histories) approach is intended to give a modern interpretation of quantum mechanics, …

— Wikipedia on Consistent histories

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It needs to be decoherent in order to be consistent.

— Me@2017-08-08 01:25:54 PM

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decoherent ~ no quantum superposition

consistent ~ classical logic can apply

— Me@2020-05-30 03:52:15 PM

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2020.05.30 Saturday (c) All rights reserved by ACHK

反貼士搵笨大行動 1.4

這五篇文章的主旨是,

「無知」即是「缺乏足夠資料」;

「無知」不是「愚蠢」。

需不需要補習的一個指標是,你在日校專心聽課後,懂不懂做以往的公開試試題?

如果你大部分試題也不懂做,那就代表了,你的日校導師,沒有提供足夠的資料給你,簡稱「無料到」。那樣,解決辦法是,找過另一位,可以提供足夠物理資料的導師。

記住,如果需要「補習」的話,重點不在於「補習」(額外上課),重點在於,你可以選擇導師。

而「選擇導師」的重點則在於「選擇」,而不在於「導師」。

有補習導師並不代表,你就會懂得做試題。

補習導師和日校導師一樣,可能提供不到足夠資料,即是「無料到」。補習導師和日校導師一樣,質素都是沒有保證的。「沒有保證」的意思是,如果補習無用,導師並不會賠償,你所損失的,大量金錢和時閶。

所以,「選擇導師」的重點在「選擇」,不在「導師」。

選擇對導師,才會有成果。

而「有料到」的導師極少,不易找到。以下是選擇導師的方法:

請到本站底部,點擊到達本人的補習網站。

該站有三篇文章:頭兩篇有關「選擇導師」的方法,尾一篇是廣告。

廣告那篇可以忽略。頭兩篇的內容,則適用於大部分人。

— Me@2020-04-25 08:08:39 AM

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2020.04.25 Saturday (c) All rights reserved by ACHK

Problem 2.2c

A First Course in String Theory

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2.2 Lorentz transformations for light-cone coordinates.

Consider coordinates \displaystyle{x^\mu = ( x^0, x^1, x^2, x^3 )} and the associated light-cone coordinates \displaystyle{x^\mu = ( x^+, x^-, x^2, x^3 )}. Write the following Lorentz transformations in terms of the light-cone coordinates.

(c) A boost with velocity parameter \displaystyle{\beta} in the \displaystyle{x^3} direction.

\displaystyle{ \begin{aligned} \begin{bmatrix} c t' \\ z' \\ x' \\ y' \end{bmatrix} &= \begin{bmatrix}         \gamma & -\beta \gamma & 0 & 0 \\         -\beta \gamma & \gamma & 0 & 0 \\              0 & 0 & 1 & 0 \\              0 & 0 & 0 & 1 \\     \end{bmatrix} \begin{bmatrix} c\,t \\ z \\ x \\ y \end{bmatrix}  \\ \end{aligned} }

~~~

\displaystyle{ \begin{aligned}  \begin{bmatrix} c t' \\ x' \\ y' \\ z' \end{bmatrix}  &= \begin{bmatrix}         \gamma & 0 & 0 &  -\beta \gamma \\         0 & 1 & 0 & 0 \\              0 & 0 & 1 & 0 \\          -\beta \gamma & 0 & 0 & \gamma \\     \end{bmatrix} \begin{bmatrix} c\,t \\ x \\ y \\ z \end{bmatrix}     \\ \end{aligned} }

\displaystyle{ \begin{aligned}  \begin{bmatrix}  1  & 1 & 0 & 0 \\  1  & -1 & 0 & 0 \\  0  & 0 & \sqrt{2} & 0 \\  0  & 0 & 0 & \sqrt{2} \\     \end{bmatrix}  \begin{bmatrix} (x^+)' \\ (x^-)' \\ y' \\ z' \end{bmatrix}  &= \begin{bmatrix}         \gamma & 0 & 0 &  -\beta \gamma \\         0 & 1 & 0 & 0 \\              0 & 0 & 1 & 0 \\          -\beta \gamma & 0 & 0 & \gamma \\    \end{bmatrix} \begin{bmatrix}  1  & 1 & 0 & 0 \\  1  & -1 & 0 & 0 \\  0  & 0 & \sqrt{2} & 0 \\  0  & 0 & 0 & \sqrt{2} \\     \end{bmatrix} \begin{bmatrix} x^+ \\ x^- \\ y \\ z \end{bmatrix} \\   \end{aligned} }

\displaystyle{ \begin{aligned}  \begin{bmatrix} (x^+)' \\ (x^-)' \\ y' \\ z' \end{bmatrix}  &= \frac{1}{2}  \begin{bmatrix} \gamma + 1 & \gamma - 1 & 0 & -\sqrt{2}\,\beta\,\gamma \\ \gamma - 1 & \gamma + 1 & 0 & -\sqrt{2}\,\beta\,\gamma \\  0 & 0 & 2 & 0 \\  - \sqrt{2}\,\beta\,\gamma & - \sqrt{2}\,\beta\,\gamma & 0 & 2 \gamma \end{bmatrix}  \begin{bmatrix} x^+ \\ x^- \\ y \\ z \end{bmatrix}  \\   \end{aligned} }

— Me@2020-04-19 11:52:09 PM

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2020.04.21 Tuesday (c) All rights reserved by ACHK

Omnipotence 4.2

When responding to the question “can X create a stone that it cannot lift”, another flawed argument is

X can create the stone that it cannot lift but it chooses not to create it. So there is no stone it cannot lift yet. So X has not failed the omnipotence test.

This argument is wrong.

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When we ask “can X choose to create a stone that it cannot lift”, we are discussing whether X has an ability. When we discuss ability, it is always about a potential, a possibility.

Y is able to do action B

always means that

“Y does B” is possible,

which is equivalent to

“Y does B” is not contradictory to any logical laws nor physical laws.

“Whether Y has already done B or will do B” is not the point.

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If we allow such “Y can do B but it chooses not to” argument, then anyone is omnipotent. For example,

Can you fly?

I can fly but I choose not to. So even though you have never seen me flying and will never see me flying, it is not because I cannot fly; it is just because I choose not to.

Can you choose to fly?

I can choose to fly but I choose not to choose to fly.

This type of arguments make the word “can“ meaningless.

— Me@2020-03-30 06:52:58 AM

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2020.04.19 Sunday (c) All rights reserved by ACHK

Superpower

Impossible self, 2 | 電腦輪迴觀 4.2

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ability 能力

~ you can access your own time to do things

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power 權力

~ weighted ability

~ amplified ability

~ super ability

~ 超過一人之力

~ you can access also our people’s time to do things

— Me@2020-04-17 09:00:44 PM

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Freedom is being able to make decisions that affect mainly you; power is being able to make decisions that affect others more than you. If we confuse power with freedom, we will fail to uphold real freedom.

— Freedom or Power?

— Bradley M. Kuhn and Richard M. Stallman

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So the term “superpower” is actually redundant, because “power” already means “super-ability”, the ability to access more than one person’s time.

— Me@2020-04-18 07:41:36 PM

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In daily life, “power” is often used as a synonym of “ability”. In this sense, “superpower” is the ability to access more than one person’s time.

In this context, with our people’s agreement, other people are your superpower. Also, you are our people’s superpower.

— Me@2020-04-18 03:58:32 PM

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2020.04.19 Sunday (c) All rights reserved by ACHK

太極滅世戰

機遇創生論 1.5

這段改編自 2010 年 4 月 18 日的對話。

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這個大統一理論的成員,包括(但不止於):

精簡圖:

種子論
反白論
間書原理
完備知識論

自由決定論

它們可以大統一的成因,在於它們除了各個自成一國外,還可以合體理解和應用。

下一個定律,就是「間書原理」。

「間書原理」的意思,其實是「陽之極為陰;陰之極為陽」。但那不易理解,所以,我在十多年前,舉了「間書」的例子:

我們平日看書時會間書:用紅筆間低重要的句子。

間書的一個極端是一句也不間。那我們就不知哪些是重要句子。

間書的另一個極端是句句間。那我們也不知哪些是重要句子。

— Me@2003-2004

其他例子有:

順其自然:在生活中百分百地「順其自然」,是一件十分不自然的事。

不要執著:要求自己在任何情況下也「不要執著」,本身是一個執著。

— 改編自李天命先生

知道這個原理後,你在生活處世,凡事就自然不會走得太盡,因為你知道,企圖走得太盡的後果是,輕則過猶不及,重則物極必反。

間書原理 水清則無魚

另外,運氣太好時,你會格外小心,因為,好事可以引發壞事,而大好事可以引發大壞事。運氣太差時,你亦不要過份擔心,因為,只要保命,運氣比「太差」更差的話,隨事引發大好事。

我一直以為,尋尋覓覓,兩把年紀,仍然未找到另一半,不幸也。但是,在 2019 滅世戰開始後,我發覺仍然單身,是極大的福份。

或許,到 2021 時,地球和我都仍然存在的話,宇宙會把我一切的夢想,化身成人,和我一同去創造,無限個嶄新的世界。

好事可以變好事

壞事可以變壞事

好事可以變壞事

壞事可以變好事

不要奢望,你可以控制到事情,向這四個方向中的哪一個去發展。你只可以引導,你只可以鼓勵,你不可以控制。

這正正呼應我剛剛講的「種子論」。你可以控制起點,卻不可以控制結果。

.

當你對「間中原理」深刻心領神會後,你不會輕易羨慕別人的「運氣」或者「天份」,因為通常,凡事有代價。看到別人好時,你反而會問:「他付出了什麼代價,作出了什麼犧牲?」

當你對「間中原理」深刻心領神會後,有時,你更可以主動使用。

例如,以前的眾多考試中,有時,有溫習的那一次,成績反而比沒有溫習的那一次低。

其實,原因並不是「有沒有溫習」本身,而是你「是不是太過刻意」,去奪取成績。

不如,你試試積極溫習,然後,不理成績地,盡情發揮。或許,你有意想不到的收穫。

(問:「不理成績」而又要「盡情發揮」?自相矛盾也?)

你只能提升獲得佳績的機會率,所以,要試前積極溫習,試試盡情發揮;但是,你卻不能直接控制,將要奪得什麼成績,所以,要「不理成績」。

又例如,你下次失眠時,你試試躺下,然後張開雙眼,嘗試迫自己清醒。或者,不知不覺間,你會睡著了。

再例如,如果你由於怕做得不好,而遲遲拖延著一些必須事務的話,你不妨反轉心態,試試在你的能力範圍內,把該事做到最差。或許那樣,你不會再拖延,反而會極早基本完成了該事,剩下了時間,給你改善那「草稿」。

間書原理 置之於死地而後生

.

主動版的「間中原理」,其實就是「種子論」。

把手緊握 什麼都沒有
把手放開 你得到一切

主動版的「間中原理」,可以戲稱為「耍太極」。

1171e-yin_and_yang

Wikipedia
public domain image
陽之極為陰 陰之極為陽

— Me@2020-04-13 06:58:18 PM

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2020.04.16 Thursday (c) All rights reserved by ACHK

CSS, 3


blockquote {
	font-family: Helvetica;
	font-style: normal;
	color: #4f7499;
	background: #EAEFF3;
	border-left: solid 2px #9ab3cb;
	padding-left: 10px;
	margin-left: 20px;
}

#infinite-handle {
	display: none;
}

.infinite-scroll #nav-below {
	display: block;
}

.infinite-scroll #content {
	margin-bottom: 0;
}

.wp-caption .wp-caption-text:before {
    display:none;
}
 
.wp-caption .wp-caption-text {
    text-align:center;
    padding:5px 7px 0;
}

— Me@2020-03-14 04:30:08 PM

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2020.03.14 Saturday ACHK

Ex 1.8.2.1 Implementation of $\delta$

Structure and Interpretation of Classical Mechanics

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b. Use your delta procedure to verify the properties of \displaystyle{\delta} listed in exercise 1.7 for simple functions such as implemented by the procedure f:

(define (f q)
  (compose
    (literal-function ’F
          (-> (UP Real (UP* Real) (UP* Real)) Real))
    (Gamma q)))

This implements an n-degree-of-freedom path-dependent function that depends on the local tuple of the path at each moment. You can define a literal two-dimensional path by

(define q (literal-function ’q (-> Real (UP Real Real))))

You should compute both sides of the equalities and subtract the results. The answer should be zero.

~~~

(define (((delta eta) f) q)
  (define (g epsilon)
    (f (+ q (* epsilon eta))))
    ((D g) 0))

(define (f q)
  (compose (literal-function 'f (-> (UP Real Real Real) Real))
           (Gamma q)))

(define eta (literal-function 'eta))

(define q (literal-function 'q))

(print-expression ((((delta eta) f) q) 't))

— Patrick Eli Catach

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(print-expression ((((delta eta) f) q) 't))
(+ (* ((D eta) t) (((partial 2) f) (up t (q t) ((D q) t)))) 
   (* (eta t) (((partial 1) f) (up t (q t) ((D q) t)))))
(show-expression ((((delta eta) f) q) 't))

d_2020_04_11__11_59_10_AM_

— Me@2020-04-11 12:01:04 PM

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2020.04.11 Saturday (c) All rights reserved by ACHK

Omnipotence 4.1

Please read these 2 posts first:

For all, 3 | Omnipotence

For all, 3.2 | Omnipotence 2

You can find them by searching “omnipotence” using this blog’s search box.

— Me@2020-04-08 03:17:34 PM

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If X is omnipotent, X can create a stone that it cannot lift. Then X is not omnipotent, because there is a stone it cannot lift. So omnipotence is a self-contradictory concept.

What if we define omnipotence not as “being able to do anything” but as “being able to do anything except logical self-contradictory ones“?

In order words, omnipotence means that being able to do anything logically possible. Omnipotence does not mean that being able to do also logically impossible things.

This re-definition is not useful, because the original meaning of “being omnipotent” already is “being able to do anything except logical self-contradictory ones“.

There is no re-definition needed. You can only say that the re-definition clarifies the original meaning of “being omnipotent”. However, this clarification cannot eliminate the self-contradictory nature of the meaning of “omnipotence” itself. For example, the following argument is wrong.

If X is omnipotent, “X can create a stone that it cannot lift” is self-contradictory because it is contradictory to “X is omnipotent”.

Since “X can create a stone that it cannot lift” is logically impossible, it should not be a requirement of being omnipotent.

This argument is wrong because:

1. “X can create a stone that it cannot lift” is not SELF-contradictory.

2. “X can create a stone that it cannot lift” is not logically impossible, because, for example, even a human being can create an object that he cannot lift. For example, human beings can create a car that no single person can lift.

Then someone might keep arguing that

But if X is omnipotent, “X can create a stone that it cannot lift” means that “X is omnipotent and X can create a stone it cannot lift”, which is logically impossible. So “X cannot create a stone that it cannot lift” does not make X non-omnipotent.

In other words, “whether X can create a stone that it cannot lift” should not be the requirement of the omnipotence test.

The argument is wrong, because what we are questioning is

Can someone X be omnipotent?

or

Is omnipotence logically possible?

.

Remember:

“Being logically possible” means “not self-contradictory”.

.

If “X is omnipotent” is true,

then “X can create a stone that it cannot lift” is true.

Then “there is a stone that X cannot lift” is true.

Then “X is not omnipotent” is true.

But “X is not omnipotent” is contradictory to the assumption “X is omnipotent“.

So “X is omnipotent” is self-contradictory.

So the question “whether an entity X can be omnipotent and create a stone that it cannot lift” is illegitimate because “an entity X is omnipotent” is logically impossible in the first place. It should not be placed within a question.

Note that our omnipotent test is

“whether an entity X can create a stone that it cannot lift”,

NOT “whether an entity X can be omnipotent and create a stone that it cannot lift”,

NOR “whether an omnipotent entity X can create a stone that it cannot lift”.

— Me@2020-03-30 06:52:58 AM

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2020.04.10 Friday (c) All rights reserved by ACHK

反貼士搵笨大行動 1.3

無足夠資料 12

.

中六時,我日校的同學中,有些在中五時和我一樣,都有補 Ken Chan 的物理班。升上中六後,他們大部分也補 MC Chan 的物理班。我在中六時則沒有補習。

哪我為什麼在中六時,不去補 MC Chan 的物理班呢?

一方面,那時我覺得,只要足夠勤力,不補也沒有大所謂。另外,補習本身,就要花很多,我原本可以用來,研習的時間。

會考的兩年課程中,因為不開心,荒廢了第一年。所以,中五時的補習,是必須的。 但是,我在預科一開始的中六時,就立刻起步讀書,所以,我覺得我可能,毋須補習物理。

思前想後,結果,我在中六升中七的暑假,才去上 MC Chan 的物理班。那算是有點兒幸運,因為太多人報讀,不一定有學位給我。我第一次上他的課時,情形如我日校同學所述,真的連桌子之間的行人路,也放了椅子坐了人。好處是,那證明了導師真的很有型。壞處是,萬一有火警的話,一定傷亡慘重。

事後看來,我當年應該要中六開始時,就補 MC Chan 的物理。

理論上,只要花得足夠多時間研習,不補習也可以獲得,補習時獲得的知識。

實際上,這個講法,就有如:「雖然我住在十二樓,但是只有花足夠多的時間,用心行樓梯,我不乘搭升降機,也可以過到快樂的生活。」

(問:那你即是贊成補習?)

你這樣問沒有意思,因為,那就好像問我,贊不贊成看醫生。那要看情況而定,不能一概而論。

需不需要補習的一個指標是,你在日校專心聽課後,懂不懂做以往的公開試試題?

你可先參考本網誌的五篇文章:

無足夠資料

自我實現預言

天人天書

無足夠資料 4

無足夠資料 5.2

這五篇文章的主旨是,

  1. 「無知」即是「缺乏足夠資料」;

  2. 「無知」不是「愚蠢」。

需不需要補習的一個指標是,你在日校專心聽課後,懂不懂做以往的公開試試題?

如果你大部分試題也不懂做,那就代表了,你的日校導師,沒有提供足夠的資料給你,簡稱「無料到」。那樣,解決辦法是,找過另一位,可以提供足夠物理資料的導師。

記住,如果需要「補習」的話,重點不在於「補習」(額外上課),重點在於,你可以選擇導師。

而「選擇導師」的重點則在於「選擇」,而不在於「導師」。

有補習導師並不代表,你就會懂得做試題。

補習導師和日校導師一樣,可能提供不到足夠資料,即是「無料到」。補習導師和日校導師一樣,質素都是沒有保證的。「沒有保證」的意思是,如果補習無用,導師並不會賠償,你所損失的,大量金錢和時閶。

所以,「選擇導師」的重點在「選擇」,不在「導師」。

選擇對導師,才會有成果。

而「有料到」的導師極少,不易找到。以下是選擇導師的方法:

— Me@2020-03-31 04:28:23 PM

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2020.04.05 Sunday (c) All rights reserved by ACHK

Pier

d_2020_03_24__22_44_50_PM_

It was a picture I drawn in 1997. It was the summer holiday after my HKCEE public exam. It was a drawing trip with my school’s Art Club. The location was Sai Kung Pier.

As far as I remember, I haven’t drawn since then. Perhaps I do not like to draw alone. Hope that one day I could find my girlfriend finally so that I have someone to draw with.

— Me@2020-03-24 10:37:58 PM

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2020.03.26 Thursday (c) All rights reserved by ACHK

Problem 2.2b

A First Course in String Theory

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2.2 Lorentz transformations for light-cone coordinates.

Consider coordinates \displaystyle{x^\mu = ( x^0, x^1, x^2, x^3 )} and the associated light-cone coordinates \displaystyle{x^\mu = ( x^+, x^-, x^2, x^3 )}. Write the following Lorentz transformations in terms of the light-cone coordinates.

(b) A rotation with angle \displaystyle{\theta} in the \displaystyle{x^1, x^2} plane.

\displaystyle{ \begin{aligned} \begin{bmatrix} c t' \\ x' \\ y' \\ z' \end{bmatrix}  &= \begin{bmatrix}       1 & 0 & 0 & 0 \\       0 & \cos \theta & -\sin \theta & 0 \\       0 & \sin \theta & \cos \theta & 0 \\       0 & 0 & 0 & 1 \\     \end{bmatrix}     \begin{bmatrix} c\,t \\ x \\ y \\ z \end{bmatrix} \\   \end{aligned} }

~~~

\displaystyle{ \begin{aligned}    \begin{bmatrix}        \frac{1}{\sqrt{2}}  & \frac{1}{\sqrt{2}} & 0 & 0 \\        \frac{1}{\sqrt{2}}  & -\frac{1}{\sqrt{2}} & 0 & 0 \\                         0  & 0 & 1 & 0 \\                         0  & 0 & 0 & 1 \\     \end{bmatrix}  \begin{bmatrix} (x^+)' \\ (x^-)' \\ y' \\ z' \end{bmatrix}  &=   \begin{bmatrix}       1 & 0 & 0 & 0 \\       0 & \cos \theta & -\sin \theta & 0 \\       0 & \sin \theta & \cos \theta & 0 \\       0 & 0 & 0 & 1 \\     \end{bmatrix}    \begin{bmatrix}        \frac{1}{\sqrt{2}}  & \frac{1}{\sqrt{2}} & 0 & 0 \\        \frac{1}{\sqrt{2}}  & -\frac{1}{\sqrt{2}} & 0 & 0 \\                         0  & 0 & 1 & 0 \\                         0  & 0 & 0 & 1 \\     \end{bmatrix}  \begin{bmatrix} x^+ \\ x^- \\ y \\ z \end{bmatrix} \\  \begin{bmatrix} (x^+)' \\ (x^-)' \\ y' \\ z' \end{bmatrix}  &= \frac{1}{2}  \begin{bmatrix} \cos\theta + 1 & 1 - \cos\theta & -\sqrt{2} \sin\theta & 0 \\  1 - \cos\theta & \cos\theta + 1 &  \sqrt{2} \sin\theta & 0 \\  \sqrt{2} \sin{\theta} & -\sqrt{2} \sin{\theta} & 2 \cos{\theta} & 0 \\ 0 & 0 & 0 & 2 \\ \end{bmatrix} \begin{bmatrix} x^+ \\ x^- \\ y \\ z \end{bmatrix}  \end{aligned} }

— Me@2020-03-22 10:16:09 PM

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2020.03.23 Monday (c) All rights reserved by ACHK

Logical arrow of time, 7.2

Microscopically, there is no time arrow.

— Me@2011.06.23

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No. There is weak force.

— Me@2011.07.22

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Myth: The arrow of time is a consequence of CP-symmetry violation.

The weak nuclear interactions violate the CP symmetry which is equivalent to saying that they violate the T symmetry. Is it the reason why eggs don’t unbreak? Of course not. There are two basic ways to see why. First, the weak interactions much like all other interactions preserve the CPT symmetry – there is extensive theoretical as well as experimental evidence supporting this assertion. And the CPT symmetry would be enough to show that eggs break as often as unbreak. More precisely, eggs break as often as mirror anti-eggs unbreak. ;-)

— Myths about the arrow of time

— Lubos Motl

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Weak force’s T-symmetry-violation has nothing to do with the time arrow.

In other words, microscopic time arrow has nothing to do with the macroscopic time arrow.

— Me@2020-03-21 07:56:01 PM

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About T-violation and the arrow of time: the simple answer is that the weak interactions are perfectly unitary, even if they are not T-invariant. They don’t affect the entropy in any way, so they don’t help with the arrow of time.

A bit more carefully: if you did want to explain the arrow of time using microscopic dynamics, you would have to argue that there exist more solutions to the equations of motion in which entropy grows than solutions in which entropy decreases. But CPT invariance is enough to guarantee that that’s not true. For any trajectory (or ensemble of trajectories, or evolution of a distribution function) in which the entropy changes in one way, there is another trajectory (or set…) in which the entropy changes in precisely the opposite way: the CPT conjugate. Such laws of physics do not in and of themselves pick out what we think of as the arrow of time.

People talk about the “arrow of time of the weak interactions,” but ask yourself: in which direction does it point? There just isn’t any direct relationship to entropy.

— Sean Carroll

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2020.03.21 Saturday (c) All rights reserved by ACHK

機遇創生論 1.4

這段改編自 2010 年 4 月 18 日的對話。

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你只能控制因,不能控制果。事情結果,除了受你的因以外,還受千百萬樣其他因素影響。所以,人生的大目標之中,很多也只有極細的成功機會率。

你唯一可以做的,就是透過嘗試掌握,最多的自然定律(道理)和具體資訊(世情/情報),去把成功的機會率,稍為提高一點。但記住,只可以提高一點,不會很多。

或者說,從來沒有必定成功的途徑,只有保證失敗的方法。而保證失敗的主要方法有:

  1. 不懂道理

  2. 懂道理但缺乏足夠情報

刪除必敗之道,就有成功之機。

這個大統一理論的成員,包括(但不止於):

精簡圖:

種子論
反白論
間書原理
完備知識論

自由決定論

它們可以大統一的成因,在於它們除了各個自成一國外,還可以合體理解和應用。

而道理和情報之中,較為常用的,有「反白論」和「間書原理」。

「反白論」的意思是,現時的地球人間,極多的情況下,名義與實情都是相反的。

反白論 ~ 名實時常相反論

例如,真正的有利健康的食品,例如蘋果,你不會刻意標籤它,為「健康食品」。市面上,刻意標籤為「健康食品」的,通常也是人工製品,營養價値不及水果高,有時甚至有害。

又例如,小學畢業和中學畢業時,紀念冊也會寫「友誼永固」,正正是友誼不會永固,通常。長大後,仍然有聯絡的兒時同學,極端接近零。從來沒有「石頭永固」的口號,因為,石頭本身就永固。

再例如,通常國家名越長,包含越多形容詞,那個國家就越危險。國名中的形容詞,往往正正就是,那個國家沒有的東西。

As a rule of thumb, the more qualifiers there are before the name of a country, the more corrupt the rulers. A country called The Socialist People’s Democratic Republic of X is probably the last place in the world you’d want to live.

–- Paul Graham

又再例如,為什麼結婚時會「山盟海誓」?

正正是因為愛情關係,可說是眾多感情關係中,最不可靠的一種;正正是因為誓詞中的承諾,很多人也不能達到。不信的話,你可以查看,離婚率的高低。

又再又例如,

我認為,對我們來說,一個人,一個黨,一個軍隊,或者一個學校,如若不被敵人反對,那就不好了,那一定是同敵人同流合污了。如若被敵人反對,那就好了,那就證明我們同敵人劃清界線了。如若敵人起勁地反對我們,把我們說得一塌糊塗,一無是處,那就更好了,那就證明我們不但同敵人劃清了界線,而且證明我們的工作是很有成績的了。

「反白論」的應用在於,掌握以後,大大減少了,你被世人欺騙得到的比例。

而更上一層樓話,你更可以反世人之言而行。例如,你選擇工作時,再不會為了一個職位的名氣大而選它,因為「名氣大」通常代表「收入少」或者「不快樂」。否則,為什麼一份工作需要用「名氣大」作賣點呢?

你不會再考慮,一份工作的名氣大小。反而,你會先考慮其短期收入和長遠收入,再考慮自己的興趣。

— Me@2020-03-19 09:34:39 PM

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2020.03.21 Saturday (c) All rights reserved by ACHK

scmutils, 3

Structure and Interpretation of Classical Mechanics

Scheme Mechanics Installation for GNU/Linux

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This post assumes that you have already installed the scmutils library and been able to open it using the standard editor Emacs.

If not, go to the bottom of this post to click the category scmutils, so that you can see all the posts in this scmutils series.

d_2020_02_22__16_02_00_PM_

Then go to the post “scmutils, 2.3.2” to follow the installation and setup instructions.

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After installing and setting up the scmutils library, you can start to use it.

d_2020_02_22__18_12_54_PM_

However, what if you want to close the Emacs editor? How to save your scheme program before closing Emacs?

By default, you cannot. So I have written a small program to help. Here is the installation instruction:

1. Go to the end of the .emacs file. Add the following code, if it does not already exist:


(defun mechanics()
  (interactive)
  (run-scheme
   "/usr/local/scmutils/mit-scheme/bin/scheme --library
/usr/local/scmutils/mit-scheme/lib"
  ))

2. Add the following code:


(fset 'set-working-dir
      (lambda (&optional arg) "Keyboard macro."
	(interactive "p")
	(kmacro-exec-ring-item
	 (quote ("(set-working-directory-pathname! 
                  \"~/Documents/\")\n" 0 "%d")) arg)))
 
(fset 'load-scm
      (lambda (&optional arg) "Keyboard macro."
	(interactive "p")
	(kmacro-exec-ring-item
	 (quote ("(load \"tt.scm\")" 0 "%d")) arg)))
 
(defun mechan ()
  (interactive)
  (split-window-below)
  (windmove-down)
  (mechanics)
  (set-working-dir)
  (comint-send-input)
  (windmove-up)			
  (find-file "~/Documents/tt.scm")
  (end-of-buffer)
  (windmove-down)
  (cond ((file-exists-p "~/Documents/tt.scm")
	 (interactive)
	 (load-scm)
	 (comint-send-input)))
  (windmove-up)
)
 
(defun cxce ()
  (interactive)
  (save-buffer)
  (windmove-down)
  (load-scm)
  (comint-send-input)
  (windmove-up)
)
 
(global-set-key (kbd "C-x C-e") 'cxce)

3. Close Emacs. Re-open it.

4. Type the command

M-x mechan

The command M-x means pressing the Alt key and x together. Then type the word mechan.

5. You will see the Emacs editor is split into two windows, one up and one down.

The lower window is the scheme environment. You can type a line of code and the press Enter to execute it.

The upper window is the editor. You can type multiple lines of code and the type

C-x C-e

to execute it. The command C-x C-e means pressing Ctrl and x together and then Ctrl and e.

d_2020_03_11__20_28_27_PM_

6. Your scheme code is saved to the following file

"~/Documents/tt.scm"

In case you need to backup your code, backup this file.

— Me@2020-03-10 10:59:45 PM

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2020.03.10 Tuesday (c) All rights reserved by ACHK