Counting states in heterotic SO(32) string theory | A First Course in String Theory

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At any mass level of the heterotic string, the spacetime bosons are obtained by “tensoring” *all* the left states (NS’+ and R’+) with with the right-moving NS+ states with .

Similarly, the spacetime fermions are obtained by tensoring all the left states (NS’+ and R’+) with with the right-moving R- states with .

c) Are there tachyonic states in heterotic string theory?

Write out the massless states of the theory (bosons and fermions) …

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— This answer is my guess. —

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The left NS’+ sector:

The left R’+ sector has no massless states.

The right-moving NS+ states:

The R- states (that used as right-moving states):

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Since R’+ has no massless states:

spacetime bosons:

spacetime fermions:

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— This answer is my guess. —

— Me@2018-12-18 07:46:15 PM

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2018.12.18 Tuesday (c) All rights reserved by ACHK