Ex 1.7 Properties of $\delta$

Let \displaystyle{F} be a path-independent function and \displaystyle{g} be a path-dependent function; then

\displaystyle{\delta_\eta h[q] = \left( DF \circ g[q] \right) \delta_\eta g[q]~~~~~\text{with}~~~~~h[q] = F \circ g[q].~~~~~(1.26)}

— 1.5.1 Varying a path

— Structure and Interpretation of Classical Mechanics

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Prove that

\displaystyle{\delta_\eta F \circ g[q] = \left( DF \circ g[q] \right) \delta_\eta g[q]}

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\displaystyle{RHS = \lim_{\Delta t \to 0} \left( \frac{F \circ g[q](t+\Delta t) - F \circ g[q](t)}{\Delta t} \right) \lim_{\epsilon \to 0} \left( \frac{g[q+\epsilon \eta]-g[q]}{\epsilon} \right)}

\displaystyle{ \begin{aligned} LHS &= \delta_\eta F \circ g[q] \\   &=  \lim_{\epsilon \to 0} \left( \frac{F \circ g[q+\epsilon \eta]-F \circ g[q]}{\epsilon} \right) \\    &=  \lim_{\epsilon \to 0} \left( \frac{F \left[ g[q+\epsilon \eta] \right] - F \left[ g[q] \right]}{\epsilon} \right) \\   \end{aligned}}

Since \displaystyle{F} is path-independent,

\displaystyle{ \begin{aligned} LHS   &= \lim_{\epsilon \to 0} \left(  \frac{F \left( g[q+\epsilon \eta ] \right) - F \left( g[q] \right)}{\epsilon} \right) \\   \end{aligned}}

Let \displaystyle{ g[q+\epsilon \eta] = g + \Delta g}.

\displaystyle{ \begin{aligned} LHS   &= \lim_{\epsilon \to 0} \left(  \frac{F \left( g[q] + \Delta g[q]] \right) - F \left( g[q] \right)}{\epsilon} \right) \\   &= \lim_{\epsilon \to 0} \left(  \frac{F \left( g[q] + \Delta g[q]] \right) - F \left( g[q] \right)}{\Delta g[q]}\frac{\Delta g[q]}{\epsilon} \right) \\   \end{aligned}}

When \displaystyle{ \epsilon \to 0}, \displaystyle{ \Delta g \to 0 }.

\displaystyle{ \begin{aligned} LHS   &= \lim_{\substack{\epsilon \to 0 \\ \Delta g \to 0}} \left(  \frac{F \left( g[q] + \Delta g[q]] \right) - F \left( g[q] \right)}{\Delta g[q]}\frac{\Delta g[q]}{\epsilon} \right) \\   &= \lim_{\Delta g \to 0} \left(  \frac{F \left( g[q] + \Delta g[q]] \right) - F \left( g[q] \right)}{\Delta g[q]} \lim_{\epsilon \to 0} \frac{g[q + \epsilon \eta] - g[q]}{\epsilon} \right) \\   &= DF \left( g[q] \right) \delta_\eta g[q] \\   &= RHS \\  \end{aligned}}

— Me@2019-06-24 10:55:28 PM

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2019.06.25 Tuesday (c) All rights reserved by ACHK