Completeness

A formal system S is syntactically complete or deductively complete or maximally complete or simply complete if and only if for each formula φ of the language of the system either φ or (not φ) is a theorem of S. This is also called negation completeness. In another sense, a formal system is syntactically complete if and only if no unprovable axiom can be added to it as an axiom without introducing an inconsistency.

Truth-functional propositional logic and first-order predicate logic are semantically complete, but not syntactically complete (for example, the propositional logic statement consisting of a single variable “a” is not a theorem, and neither is its negation, but these are not tautologies). Godel’s incompleteness theorem shows that any recursive system that is sufficiently powerful, such as Peano arithmetic, cannot be both consistent and complete.

— Wikipedia on Completeness

2012.12.11 Tuesday ACHK

The War of the Worlds

Animal Rights activist David McKnight, writing in the November 2004 issue of Human and Animal Rights, noted that at least five vegetarians and animal rights activists known to him personally were substantially influenced to take their stance by reading Wells’ book, which vividly conveys human beings’ horror at becoming in effect the Martians’ food animals. He surmises that many other people may have been similarly affected, though it might not have been Wells’ intention to propagate vegetarianism. In many passages, an explicit comparison is drawn between the Martians’ treatment of humans and the humans’ own treatment of cows, rabbits, rats, ants and other creatures which mankind in one way or another treads underfoot.

— Wikipedia on The War of the Worlds

— 22:33, 18 July 2006

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2012.12.10 Monday ACHK

百年樹人

伸張智力 2

這段改編自 2010 年 4 月 3 日的對話。

(安:我發覺我和你的學術智力水平,還有一點差距。而那一點的差距,在個別的知識範疇,可能價值一世人的時間。)

有沒有那麼誇張?我也只是用了三十年,而不是一世人的時間,去學那些知識。

(安:一點也不誇張。我和你所談論的話題,大部分人可能一世人也不會明白。例如,剛才我們研究「機會率的詮釋」。試想想,有多少人會明白,什麼是「機會率」呢?)

可以這樣說。但是,現在是講「你」,而不是講「一般人」。現在是比較你和我的水平,而不是比較你我和一般人。

(安:即使只比較你和我,我剛才都講過,有些問題,如果不是因為跟你對話,我自己是想不通的。我不是指所有課題。我的意思是,在某一些領域,我一生人也不會自己發現,那些問題的解答。)

假設在「電腦程式編寫」這個範疇,我有十年的功力。理論上,大概而言,只要你肯花十年的時間,你也可以得到同樣的功力。

— Me@2012.12.09

2012.12.10 Monday (c) All rights reserved by ACHK

機會率哲學 5

Interpretations of probability | Tree diagram 2

For a fraction representing a probability, the denominator is the known.

In a tree diagram, the starting point is the known.

conditional probability

= changing the denominator

= changing the starting point of a tree diagram

— Me@2012.12.07

2012.12.09 Sunday (c) All rights reserved by ACHK

Move on

Yes, this city needs Bruce Wayne. Your resources, your knowledge… not your body. Not your life. That time has passed.

Remember when you left Gotham? Before all this, before Batman? You were gone seven years. Seven years I waited, hoping that you wouldn’t come back. Every year, I took a holiday. I went to Florence, there’s this cafe, on the banks of the Arno. Every fine evening, I’d sit there and order a Fernet Branca. I had this fantasy, that I would look across the tables and I’d see you there, with a wife and maybe a couple of kids. You wouldn’t say anything to me, nor me to you. But we’d both know that you’d made it, that you were happy. I never wanted you to come back to Gotham. I always knew there was nothing here for you, except pain and tragedy. And I wanted something more for you than that. I still do.

Alfred Pennyworth: I’ll get this to Mr. Fox, but no more. I’ve sewn you up, I’ve set your bones, but I won’t bury you. I’ve buried enough members of the Wayne family.

Bruce Wayne: You’ll leave me?

Alfred Pennyworth: You see only one end to your journey. Leaving is all I have to make you understand, you’re not Batman anymore. You have to find another way. You used to talk about finishing a life beyond that awful cape.

— The Dark Knight Rises

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2012.12.08 Saturday ACHK

進步成本估算

這段改編自 2012 年 12 月 6 日的對話。

如果你想數學成績,有明顯的進步,你就要有基本的盤算。你要知道,大概每做多少道練習題目,你才會在考試中進步一分。然後,再問自己,你想進步多少分。 

如果你平均每做二十道題目,就會進步一分,而你想進步的分數是,至少十分的話,你就要在試前,試做和改正,起碼二百道題目。

— Me@2012.12.08

2012.12.08 Saturday (c) All rights reserved by ACHK

Godel 7

The branch of mathematical logic that deals with what is true in different models is called model theory. The branch called proof theory studies what can be formally proved in particular formal systems. The completeness theorem establishes a fundamental connection between these two branches, giving a link between semantics and syntax.

The completeness theorem should not, however, be misinterpreted as obliterating the difference between these two concepts; in fact Godel’s incompleteness theorem, another celebrated result, shows that there are inherent limitations in what can be achieved with formal proofs in mathematics.

The name for the incompleteness theorem refers to another meaning of complete (see model theory – Using the compactness and completeness theorems). In particular, Godel’s completeness theorem deals with formulas that are logical consequences of a first-order theory, while the incompleteness theorem constructs formulas that are not logical consequences of certain theories.

— 14 February 2012

— Wikipedia on Godel’s completeness theorem

2012.12.07 Friday ACHK

伸張智力

這段改編自 2010 年 4 月 3 日的對話。

(安:我發覺有些問題,如果不是因為跟你對話,我自己是想不通的。)

倒轉來說都可以。如果你是因為你問我,我又不會無緣無故,思考那些問題。

(安:例如,原來剛才的「原因」問題,我在不知不覺間,偷換了話題。而那又可以引申到「機會率詮釋」的討論。)

所以,如果這個世界,有多一點類似我們這種,喜歡討論有趣話題的生物,我的日子會過得開心一點。因為那樣,我的才能得以發揮,正義得以伸張。

— Me@2012.12.06

2012.12.06 Thursday (c) All rights reserved by ACHK

The problem of induction 2

Occam’s razor 2

If induction has worked in the past, it is a simpler theory that it will continue to work, than it will stop working at precisely midnight, because the theory that it will stop working has to contain additional information specifying when it will stop working.

Marcus Hutter, in 2005, demonstrated that simpler theories are ([given that] all other things being equal) more likely to be true.

This gives us the bootstrap we need to have as least a minimal reason to trust induction that doesn’t require inductive reasoning.

— 31 August 2012 11:20:20AM

— Douglas_Reay

— Less Wrong

2012.12.05 Wednesday ACHK

Genius 2

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All children are born geniuses;

9999 out of every 10000 are swiftly,

inadvertently degeniusized by grownups.

– Buckminster Fuller

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The way to be a genius is to REALIZE that you are already one

as long as you can keep your child-self

against all the evils in the world.

– Me@2010.01.01

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2010.05.28 Friday (c) All rights reserved by ACHK

並聯電阻

這段改編自 2010 年 6 月 8 日的對話。

計算並聯電路(parallel circuit)等價電阻(equivalent resistance)的公式是

1/R = 1/R_1 + 1/R_2

但是,除非有三個或以上的電阻,否則,千萬不要用這一個版本,因為運算太繁複。步驟越多,時間就越長,而犯錯的機會亦會越大。簡言之,費時失事也。

你應改為使用高速版:

R = R_1 R_2 / (R_1 + R_2)

這版本的背誦亦不難,只要你記住「相乘除以相加」便行。

— Me@2012.12.04

2012.12.04 Tuesday (c) All rights reserved by ACHK

Godel 6

This theorem implies that the only way a language can be incomplete is [that] there is a model of the language in which a particular statement is true, and another in which the statement is false.

For example, we can see that [for] the language [comprising] the symbols 0, 1, +, -, and , [] the statement []   is true [] if we take the structure to be C or R, but not if we choose Q. So it is clear that the formula a*a = 2 is not true in every model of the language and the thus the language is incomplete.

What the completeness theorem asserts is that this is the only way that a theory (set of formulas) can be incomplete and that every formula that satisfies every structure is provable in the language.

— Godel’s Completeness And Incompleteness Theorems

— Ben Chaiken

2012.12.04 Tuesday ACHK

第 N 減 1 步

背誦製成品 10

這段改編自 2012 年 12 月 2 日的對話。

這一題用這個方法,就可以輕易完成。

(A:真的嗎?好像很難會想得到。)

你覺得很難,正正是因為你以為,需要由自己想得到。但是,現在我並不是要求你自己創作方法,而是要求你記得我教你的方法,然後在考試時見到同類題目時,可以高速拿出來運用。

情形就製作三文治前,我叫你準備材料,例如兩片麵包。如果你問:「真的嗎?好像很難才會弄到一片麵包。試想想,由種小麥開始,到製成一片麵包,有很多工序,很辛苦啊!」

我就會答:「但是,現在我並不是要求你,自己製作麵包,而是要求你,先買兩片麵包回來,然後用來製作三文治。」

記住,正常的考試,並不會要求你,由起點「第一步」開始,走到目的地「第 N 步」。大概而言,考試只會要求你由「第 N – 1 步」,走到「第 N 步」。只要你肯先行背誦,常用的高深方法,你在考試作答題目時,就可以由「第 N – 1 步」開始,輕易走到「第 N 步」。

— Me@2012.12.02

2012.12.03 Monday (c) All rights reserved by ACHK

Bell’s theorem, 5

De Broglie–Bohm theory, 4

[guess]

The spirit of de Broglie–Bohm theory is non-local realism.

The particles can be regarded as being “actually” in eigenstates with respect to any variables, even before any measurements, as long as somehow, we take into account the fact that each particle is influenced by all other particles in the universe, creating the “illusion” of superposition of eigenstates.

— Me@2012.12.01

2012.12.03 Monday (c) All rights reserved by ACHK

Results

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Mathematicians won the war.

Mathematicians broke the Japanese codes and built the A-bomb.

Mathematicians… like you.

In medicine or economics,

in technology or in space,

battle lines are being drawn.

To triumph we need results — publishable, applicable results.

Now, who among you will be the next Morse,

the next Einstein?

Who among you will be the vanguard of democracy, freedom and discovery?

Today we bequeath America’s future into your able hands.

Welcome to Princeton, gentlemen.

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– A Beautiful Mind (2001)

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2009.09.11 Friday ACHK

Monty Hall problem 1.5.4

機會率哲學 4.1.4

這段改編自 2010 年 4 月 3 日的對話。

主持人選擇先打開哪一扇門,其實受制於參賽者的原初選擇,是否房車。換句話說,「房車在第一扇門後面,而主持人打開第三扇」和「房車在第二扇門後面,而主持人打開第三扇」這兩個遊戲中途結果,是不對稱的,因為兩者有著不同的歷程。既然不等價,機會率就自然不同。

(安:我同意這個想法,會得到這個結論。但是,如果我用另一個想法,卻會得出另一個結論。

假設原本的參賽者叫做「甲」,而在遊戲中途,會加入另一位參賽者「乙」。主持人在打開第三扇門後,會改為叫乙,為甲繼續選擇。亦即是話,乙要為甲決定,究竟是選第一道門,還是第二道門。如果乙的選擇可為甲贏得房車,乙自己亦會獲得一千元的獎金。

那樣,對於乙來說,他見到的,就只是一個「二選其一」的「開門抽獎遊戲」。

如果主持人沒有任何提示,乙就只會知道「那裡有兩道門」、「一道有房車」和「另一道有山羊」,而不會掌握任何其他資料。換而言之,乙對第一第二道門,無所偏好。所以,兩道門的中獎機會率,理應相同,都是二分之一。

我這個想法有錯嗎?)

如果乙在兩門選其一時,不知道甲的原本選擇,你的講法就是正確的。兩門的中獎機會相同,都是二分之一。

但是,如果乙知道甲的原選,兩門的歷史,相對乙來說,就會不同。所以,機會率不會均等。

— Me@2012.12.02

2012.12.02 Sunday (c) All rights reserved by ACHK

Godel 5

Now when you combine the Completeness and Incompleteness Theorems, you can get some really remarkable results. If you work with the axioms of number theory, call them N (which include many of the above axioms F along with axioms for < and axioms for mathematical induction), for example, we know by the Incompleteness Theorem that there is a statement X such that neither X nor (not X) is provable. Hence, by the Completeness Theorem, there is a model of N in which X is true and a model of N in which X is false.

It follows that there are mathematical universes which look and act very much like the regular natural numbers, but do in fact have some subtle differences. One of the most fascinating results I’ve seen is that there is a model of number theory which “thinks” (in a precise sense) that the axioms N are inconsistent, even though they are not (roughly, the “proof” of an inconsistency that it “sees” is infinitely long, and so is not a real proof).

— Godel’s Completeness Theorem

— Joe Mileti

2012.12.02 Sunday ACHK